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I. Review of Word Problem Concepts
wA. Percentages
wB. Interest, Discount, and Markups
wC. Progressions
wD. Uniform Motion
wE. Work
wF. Ratio and Propotion
wG. Grouping and Counting
wH. Data Interpretation
wI. Symbols
wJ. Progressions

     

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D. Uniform Motion

     When an object is moving at a constant speed (or velocity), the object is traveling with uniform motion. The distance, D, that the object will travel in time, T, depends on the velocity, V. It is expressed mathematically as

D = VT

     If we desire the distance in miles, we usually express the velocity in miles per hour (mph) and time in hours. If the distance is in kilometers, then the velocity would be in kilometers per hour (kph).

 

Example 15

A biker travels 60 miles in 2.5 hours. Determine the biker's average speed.



Solution
The equation relating distance, velocity and time provides

60 = V(5/2)

Divide both sides by 5/2 to solve for V.

V = (60)2/5 = 24 miles/hour

 

Example 16

A car travels between two cities 400 miles apart in 7 hours. The return trip takes 9 hours. Find the average speed of the car.





Solution
The total distance is 2(400) = 800 miles. The total time is 7 + 9 = 16 hours. The average speed is found from D = VT:

800 = V(16)

V = 800/16 = 50 miles/hour


Example 17

A police officer, traveling at 100 miles per hour, pursues Philip who has a 30 minute head start. The police officer overtakes Philip in two hours. Find Philip's speed.




Solution
Let x miles per hour be Philip's speed. The distance traveled by the officer equals the distance traveled by Philip:

2 × 100 = (2 + 30/60)x

200 = (2 + 0.5)x

200 = 2.5x therefore x = 80 mph

 

w E. Ratio and Proportion





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