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I. Review of Word Problem Concepts
wA. Percentages
wB. Interest, Discount, and Markups
wC. Progressions
wD. Uniform Motion
wE. Work
wF. Ratio and Propotion
wG. Grouping and Counting
wH. Data Interpretation
wI. Symbols
wJ. Progressions

     

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 Word Problems use simple math concepts and apply them in a contorted and complicated manner. The usual strategy to solve a Word Problem is to express the question as a mathematical equation letting x, or some other letter, represent the quantity that we wish to determine.

 

         The five step process for Word Problems:

1. Quickly read the question and the answer choices to get a feel for what the question is specifically asking.

2. Read the question again (on the GMAT you have nearly two minutes per math question, so there is time to spare as long as you budget it properly--read Chapter One for pacing information).

3. Translate the equation to paper and translate the question into an expression with variables.

4. If you get a mental block or see a shortcut, use Backsolving (take numbers and feed them into the question--either answer choices or numbers you choose).

5. If that does not work, start eliminating answers that are outside of the ballpark; guess and move on.

I. Review of Word Problem Concepts

A. Percentages
B. Interest, Discount, and Markups
C. Progressions
D. Uniform Motion
E. Work
F. Ratio and Proportion
G. Grouping and Counting
H. Tables, Charts, and Graphs (Data Interpretation)
I.  Symbols
J. Progressions

A. Percentages

      The word percent is abbreviated by the symbol % and is a fraction whose denominator is 100. 26% is equivalent to the fraction 26/100. To change a decimal number to a percent, we simply multiply by 100; the number 0.321 is equivalent to 32.1%. If a percentage is given, move the decimal two places to the left to express its equivalent decimal form.


Example 1

Convert 4% into a decimal and a fraction in lowest terms.



Solution
To convert 4% into a decimal, we move the decimal point two places to the left:
4% = 0.04

To express 4% as a fraction, we divide by 100:
4/100 = 1/25

Hence,

4% = 0.04 = 1/25


Example 2

If the price of a stock falls from $50 to $40, what is the percentage of decrease?




Solution
First, subtract the numbers resulting in the decrease: 50 - 40 = 10. Then divide by the original amount:
(50 - 40) / 50 = 10 / 50 = .2

Convert to a percentage by moving the decimal point two places to the right:
% decrease = 20%




Example 3

An employee is to mark up a piece of jewelry 120%. If it cost $100, what should its selling price be?




Solution
The amount of the markup is 1.2 × 100= $120

The selling price is then $100 + $120 = $220

 


Example 4

A college bookstore purchases trade books on a 40% margin, i.e., it purchases a trade book for 40% less than its retail price. What is the percentage markup based on its wholesale price?

 
 

Solution
Since the retail price is not given, the percentage markup that we seek must be the same for all trade books. Therefore, let the retail price of a trade book be $100 (rather than the symbol x). Then the bookstore's purchase price is

100 - 100 × 0.4 = 100 - 40 = $60

If a book sells for $100 and costs $60, its percentage markup is
%markup = (100 - 60) / 60 × 100 = 40 / 60 x 100 = 66%


Example 5

Kathy buys a bike for $240 after a 40% markdown. What was the original price?

 

Solution
Let P be the original price. Then
P - P × 0.4 = 240
0.6P = 240
divide both sides by .6

therefore, P = $400



Example 6

Find the number of residents of a city if 20% of them, or 6,200 people, ride bicycles.

 

Solution
Let R be the number of residents. The equation that represents the verbal statement is
0.2R = 6,200. R = 6200/.2 = 62000/2 = 31,000 people.



Example 7

Kent pays 20% taxes on income between $10,000 and $20,000 and 30% on income over $20,000. The first $10,000 is tax free. If he pays $14,000 in taxes, what was his income?



Solution
Let Kent's income be L. Then the total tax is

0.2(20,000 - 10,000) + 0.3(L - 20,000) =14,000

2,000 + 0.3L - 6,000 = 14,000

0.3L = 14,000 + 4,000 = 18,000

L = 18,000/.3 = $60,000




Example 8

How many gallons of pure water must be added to 100 gallons of a 4% saline solution to provide a 1% saline solution?


 

Solution
Let x be the gallons of pure water to be added. There are 100 × 0.04 = 4 gallons of salt and 96 gallons of pure water in a 4% saline solution. The total number of gallons will be x + 100. The amount of salt will remain constant. Hence,

0.01(x + 100) = 4

0.01x + 1 = 4

0.01x = 3

x = 3/.01 = 300 gallons




w B. Interest, Discount, and Markups





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