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I. Review of Word Problem Concepts
wA. Percentages
wB. Interest, Discount, and Markups
wC. Progressions
wD. Uniform Motion
wE. Work
wF. Ratio and Propotion
wG. Grouping and Counting
wH. Data Interpretation
wI. Symbols
wJ. Progressions

     

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E. Work

     The amount of work, W, accomplished in time, T, depends on the rate, R, at which the work is being accomplished. Work problems are quite similar to the problems of uniform motion. The equation we use is

W = RT

     Try to solve by determining the rate per time period (usually per hour or per minute). The rate, R, is most often expressed as the job to do divided by the time, where W = 1 job. For example, a tractor plows 1/10 of a field each hour; the job is one field, so the rate is 1/10 of a field per hour. If it takes x tractors to do one job in 1 hour, then each tractor works at a rate of 1/x of the job per hour. If it takes x tractors 4 hours to do one job, then each tractor works at one quarter of the previous rate, or at the rate of 1/4x of the job per hour. In general, if it takes x tractors y hours to do one job, the rate that each tractor works is 1/(x × y) of the job per hour.

Example 18

It takes 3 men 8 hours to paint a house. How long will it take 5 men to paint the same house?


Solution
The per hour rate at which each man works is

R = 1/(3 x 8) = 1/24 houses per hour

The rate for 5 men is (5R). The work is 1 house. Our equation gives us

1 = 5/24T

Therefore, T = 24/5 = 4.8 hours or 4 hours and 48 minutes.

NOTE: 0.8 hours is 0.8 × 60 = 48 minutes.


Example 19


Michelle can input a day's invoices into the computer system in 40 minutes, and John can input the same invoices in 60 minutes. How long will it take both of them, working simultaneously, to input the invoices?



Solution

Michelle's rate for doing the job is 1/40 of the job per minute. John's rate is 1/60 of the job per minute. Let the time they work be T. Then the sum of the work that Michelle does and the work that John does must equal one job:

1=(1/40)T + (1/60)T

This is most easily solved by multiplying by 40(60):

40(60) = [40(60)]/40 × T + [40(60)]/60 × T

2400 = 60T + 40T

T = 24 minutes


Example 20

Kelly and Shelley can type the manuscript in 8 hours. Kelly can type the manuscript alone in 20 hours. How long would it take Shelley to type the manuscript?




Solution
The rate that Kelly works is 1/20 of the job per hour. Let the rate that Shelley works be R. To do one job in 8 hours we have

1 = 1/20(8) + R(8)

To solve for R, multiply by 20:

20 = 8 + 20R(8)

12 = 8(20)R

Therefore, R = 12/[8(20)] = 3/40 of the job per hour.

To type the entire manuscript alone, Shelley takes

    T = W/R = 1/(3/40) = 40/3 = 13 1/3 or 13 hours and 20 minutes.

w F. Ratio and Propotion





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